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-4.9x^2-3.5x+2.4=0
a = -4.9; b = -3.5; c = +2.4;
Δ = b2-4ac
Δ = -3.52-4·(-4.9)·2.4
Δ = 59.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{59.29}}{2*-4.9}=\frac{3.5-\sqrt{59.29}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{59.29}}{2*-4.9}=\frac{3.5+\sqrt{59.29}}{-9.8} $
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